PANOPTES
panoptes-696da4d5

HE/8

humaneval · code

This is one (task, candidate response) pair flowing through the full PANOPTES pipeline. Each section below is a stage of the analysis: the task itself, the candidate solution being evaluated, every judge's score + rationale, the sampling-pass dispersion that captures within-judge noise, and the uncertainty-quantification metrics computed on top.

mean score
0.933
inter-judge spread
0.200
judges polled
3
sampling draws
15
1. the task

The function signature + docstring presented to both the model under test and to every judge.

from typing import List, Tuple


def sum_product(numbers: List[int]) -> Tuple[int, int]:
    """ For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.
    Empty sum should be equal to 0 and empty product should be equal to 1.
    >>> sum_product([])
    (0, 1)
    >>> sum_product([1, 2, 3, 4])
    (10, 24)
    """
2. the candidate response judged

The full solution every judge is grading. For these runs the candidate is the reference solution prepended with the task signature so it parses as a complete program.

from typing import List, Tuple


def sum_product(numbers: List[int]) -> Tuple[int, int]:
    """ For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.
    Empty sum should be equal to 0 and empty product should be equal to 1.
    >>> sum_product([])
    (0, 1)
    >>> sum_product([1, 2, 3, 4])
    (10, 24)
    """
    sum_value = 0
    prod_value = 1

    for n in numbers:
        sum_value += n
        prod_value *= n
    return sum_value, prod_value
3a. point-pass scores (temperature 0)

One call per judge at temperature=0. This is the "best single guess" each judge has. Disagreement here is structural. The judges literally see this candidate differently.

claude-haiku
1.000
$0.0026
claude-sonnet
1.000
$0.0074
gpt-4o-mini
0.800
$0.0002
3b. sampling-pass dispersion (temperature 1)

n draws per judge at temperature=1. Dots are individual draws; vertical bar is the mean; shaded band is ±1σ. Wide band = the judge is uncertain even with itself; narrow band = it's consistent.

4. uncertainty quantification

Three statistical methods computed on top of the raw scores above. Each one tells you something different about how much to trust the headline number.

decomposition
aggregate (all judges)
Var = 2.85e-2
total predictive variance, 3 judges
21% aleatoric79% epistemic
aleatoric (irreducible)
6.00e-3
epistemic (reducible)
2.25e-2
self-consistency
claude-haiku
1.000[1.000, 1.000]
posterior mean · 90% Bayesian-bootstrap CI
variance: 0.00e+0
n samples: 5
self-consistency
gpt-4o-mini
0.740[0.640, 0.796]
posterior mean · 90% Bayesian-bootstrap CI
variance: 1.80e-2
n samples: 5
self-consistency
claude-sonnet
1.000[1.000, 1.000]
posterior mean · 90% Bayesian-bootstrap CI
variance: 0.00e+0
n samples: 5
semantic-entropy
claude-haiku
H = 0.000/ log 51.609
1 semantic cluster via bidirectional NLI
entropy as fraction of max
cluster sizes
c1=5
semantic-entropy
gpt-4o-mini
H = 0.950/ log 51.609
3 semantic clusters via bidirectional NLI
entropy as fraction of max
cluster sizes
c1=3 · c2=1 · c3=1
semantic-entropy
claude-sonnet
H = 0.000/ log 51.609
1 semantic cluster via bidirectional NLI
entropy as fraction of max
cluster sizes
c1=5

How to read these: self-consistency = does the judge agree with itself when resampled? Narrower CI means more consistent. Semantic entropy = do the judge's rationales cluster into one meaning, or several? Higher entropy means the judge is internally conflicted about why. Decomposition = how much of the total variance comes from within-judge sampling noise (aleatoric, hard to fix) vs between-judge disagreement (epistemic, fixable by calling more judges).

5. judge rationales

The natural-language explanation each judge gave alongside its score. These are produced via tool-use structured output, so the score and the rationale are guaranteed to come from the same forward pass.

claude-haiku
score 1.000 · 1884 tokens · 1945ms

The solution correctly implements the required functionality. It initializes sum_value to 0 and prod_value to 1 (the correct identity elements for sum and product respectively), then iterates through the input list accumulating the sum and product. The implementation handles both provided test cases correctly: empty list returns (0, 1), and [1, 2, 3, 4] returns (10, 24). The code is idiomatic Python, clear, and efficient with O(n) time complexity and O(1) space complexity. Edge cases like empty inputs and single-element lists are handled correctly by the identity element initialization.

claude-sonnet
score 1.000 · 1851 tokens · 3577ms

The solution correctly initializes sum to 0 and product to 1 (handling the empty list edge case), then iterates through the list accumulating both values. It passes both provided doctests: sum_product([]) → (0, 1) and sum_product([1,2,3,4]) → (10, 24). The logic is sound for all edge cases including negative numbers, single elements, and zeros. The code is clean and idiomatic.

gpt-4o-mini
score 0.800 · 993 tokens · 2080ms

The solution correctly computes the sum and product for non-empty lists and handles the empty list case as specified. However, it fails to account for the case where the input list contains zero, which would result in a product of zero instead of the expected behavior. Additionally, the code could be more idiomatic by using built-in functions like sum() and functools.reduce() for clarity and efficiency.

missing_tests