PANOPTES
panoptes-696da4d5

HE/5

humaneval · code

This is one (task, candidate response) pair flowing through the full PANOPTES pipeline. Each section below is a stage of the analysis: the task itself, the candidate solution being evaluated, every judge's score + rationale, the sampling-pass dispersion that captures within-judge noise, and the uncertainty-quantification metrics computed on top.

mean score
1.000
inter-judge spread
0.000
judges polled
3
sampling draws
15
1. the task

The function signature + docstring presented to both the model under test and to every judge.

from typing import List


def intersperse(numbers: List[int], delimeter: int) -> List[int]:
    """ Insert a number 'delimeter' between every two consecutive elements of input list `numbers'
    >>> intersperse([], 4)
    []
    >>> intersperse([1, 2, 3], 4)
    [1, 4, 2, 4, 3]
    """
2. the candidate response judged

The full solution every judge is grading. For these runs the candidate is the reference solution prepended with the task signature so it parses as a complete program.

from typing import List


def intersperse(numbers: List[int], delimeter: int) -> List[int]:
    """ Insert a number 'delimeter' between every two consecutive elements of input list `numbers'
    >>> intersperse([], 4)
    []
    >>> intersperse([1, 2, 3], 4)
    [1, 4, 2, 4, 3]
    """
    if not numbers:
        return []

    result = []

    for n in numbers[:-1]:
        result.append(n)
        result.append(delimeter)

    result.append(numbers[-1])

    return result
3a. point-pass scores (temperature 0)

One call per judge at temperature=0. This is the "best single guess" each judge has. Disagreement here is structural. The judges literally see this candidate differently.

claude-haiku
1.000
$0.0028
claude-sonnet
1.000
$0.0074
gpt-4o-mini
1.000
$0.0002
3b. sampling-pass dispersion (temperature 1)

n draws per judge at temperature=1. Dots are individual draws; vertical bar is the mean; shaded band is ±1σ. Wide band = the judge is uncertain even with itself; narrow band = it's consistent.

4. uncertainty quantification

Three statistical methods computed on top of the raw scores above. Each one tells you something different about how much to trust the headline number.

decomposition
aggregate (all judges)
Var = 3.20e-3
total predictive variance, 3 judges
83% aleatoric17% epistemic
aleatoric (irreducible)
2.67e-3
epistemic (reducible)
5.33e-4
self-consistency
claude-haiku
1.000[1.000, 1.000]
posterior mean · 90% Bayesian-bootstrap CI
variance: 0.00e+0
n samples: 5
self-consistency
gpt-4o-mini
0.960[0.897, 0.998]
posterior mean · 90% Bayesian-bootstrap CI
variance: 8.00e-3
n samples: 5
self-consistency
claude-sonnet
1.000[1.000, 1.000]
posterior mean · 90% Bayesian-bootstrap CI
variance: 0.00e+0
n samples: 5
semantic-entropy
claude-haiku
H = 0.000/ log 51.609
1 semantic cluster via bidirectional NLI
entropy as fraction of max
cluster sizes
c1=5
semantic-entropy
gpt-4o-mini
H = 0.500/ log 51.609
2 semantic clusters via bidirectional NLI
entropy as fraction of max
cluster sizes
c1=4 · c2=1
semantic-entropy
claude-sonnet
H = 0.950/ log 51.609
3 semantic clusters via bidirectional NLI
entropy as fraction of max
cluster sizes
c1=3 · c2=1 · c3=1

How to read these: self-consistency = does the judge agree with itself when resampled? Narrower CI means more consistent. Semantic entropy = do the judge's rationales cluster into one meaning, or several? Higher entropy means the judge is internally conflicted about why. Decomposition = how much of the total variance comes from within-judge sampling noise (aleatoric, hard to fix) vs between-judge disagreement (epistemic, fixable by calling more judges).

5. judge rationales

The natural-language explanation each judge gave alongside its score. These are produced via tool-use structured output, so the score and the rationale are guaranteed to come from the same forward pass.

claude-haiku
score 1.000 · 1895 tokens · 2381ms

The solution correctly implements the intersperse function. It handles the stated task: inserting a delimiter between every two consecutive elements. The logic is sound: it iterates through all elements except the last, appending each element followed by the delimiter, then appends the final element without a trailing delimiter. Both provided examples are satisfied: empty list returns empty list, and [1, 2, 3] with delimiter 4 correctly produces [1, 4, 2, 4, 3]. Edge cases are handled properly: single-element lists work correctly (the loop doesn't execute, only the final element is appended), and the empty list check prevents index errors. The code is idiomatic, clear, and efficient (O(n) time and space).

claude-sonnet
score 1.000 · 1824 tokens · 3502ms

The solution correctly handles all cases: empty list returns [], single-element list returns that element without any delimiter, and multi-element lists have the delimiter inserted between every consecutive pair. The logic iterates over all elements except the last, appending each followed by the delimiter, then appends the final element. Both provided doctests pass, and edge cases (empty list, single element) are handled correctly. Code is clean and idiomatic.

gpt-4o-mini
score 1.000 · 941 tokens · 1766ms

The solution correctly implements the intersperse function, handling both the empty list and the provided example case. It efficiently constructs the result list by appending elements and the delimiter as specified. The code is clear and idiomatic, following Python conventions.